Re: Draft 2: Playoffs
Posted: Wed Apr 15, 2020 6:43 pm
OK to answer a few questions and to illustrate how simple my system is I'll show you guys how its done with an example to follow in the next post below:
A cricket game is based on 2 major components, batting and bowling (the bowling stats generally include ground fielding misfields and misthrows are counted against the bowler). Therefore what I will do is normalize the batting and bowling and WK performance (ie create a Z-score) of each team into a composite team score. This will allow us to equate between batting performances and bowling performances, because runs and wickets are entirely different units of measure. Hence the z-scores.
The team with the highest composite score wins the game, even if their batting or bowling performance was better than the other teams. Its not only fair, but stays as true to the actual game of cricket as possible.
So just using a team comprised of 2 batsmen and 2 bowlers here's how it would work:
Team A (bat 1, bat 2, bowler 1, bowler 2)
Team B (bat 3, bat 4, bowler 3, bowler 4)
bat 1 random innings is 15 off 25 balls
bat 2 random innings is 63 off 70 balls
bat 3 random innings is 37 off 49 balls
bat 4 random innings is 43 off 45 balls
bowler 1 random innings is 30 average, 3.00 econ
bowler 2 random innings is N/A average, 5.50 econ
bowler 3 random innings is 15 average, 6.00 econ
bowler 4 random innings is 20 average, 4.00 econ
The averages and strike rates/bowling econ of each player would be divided by the global mean statistic of each to get their normalized batting/bowling score. A bowler who doesn't take a wicket will be judged solely on his economy rate in that innings. Those normalized scores would either be added or averaged to get the team total score:
Team A bat score: (15/30)*(60/75) + (63/30)*(90/75) = 0.40 + 2.52 = 2.92
Team A bowl score: (30/30)*(5.00/3.00) + (5.00/5.50) = 1.67 + 0.91 = 2.58
Team Total score : 2.92 + 2.58 = 5.50
Team B bat score: (37/30)*(75.5/75) + (43/30)*(95.56/75) = 1.25 + 1.83 = 3.08
Team B bowl score: (30/15)*(5.00/6.00) + (30/20)*(5.00/4.00) = 1.66 + 1.88 = 3.54
Team B total score: 3.08 + 3.54 = 6.62
Thus Team B would win the head to head matchup by a score of 6.62 to 5.50.
A cricket game is based on 2 major components, batting and bowling (the bowling stats generally include ground fielding misfields and misthrows are counted against the bowler). Therefore what I will do is normalize the batting and bowling and WK performance (ie create a Z-score) of each team into a composite team score. This will allow us to equate between batting performances and bowling performances, because runs and wickets are entirely different units of measure. Hence the z-scores.
The team with the highest composite score wins the game, even if their batting or bowling performance was better than the other teams. Its not only fair, but stays as true to the actual game of cricket as possible.
So just using a team comprised of 2 batsmen and 2 bowlers here's how it would work:
Team A (bat 1, bat 2, bowler 1, bowler 2)
Team B (bat 3, bat 4, bowler 3, bowler 4)
bat 1 random innings is 15 off 25 balls
bat 2 random innings is 63 off 70 balls
bat 3 random innings is 37 off 49 balls
bat 4 random innings is 43 off 45 balls
bowler 1 random innings is 30 average, 3.00 econ
bowler 2 random innings is N/A average, 5.50 econ
bowler 3 random innings is 15 average, 6.00 econ
bowler 4 random innings is 20 average, 4.00 econ
The averages and strike rates/bowling econ of each player would be divided by the global mean statistic of each to get their normalized batting/bowling score. A bowler who doesn't take a wicket will be judged solely on his economy rate in that innings. Those normalized scores would either be added or averaged to get the team total score:
Team A bat score: (15/30)*(60/75) + (63/30)*(90/75) = 0.40 + 2.52 = 2.92
Team A bowl score: (30/30)*(5.00/3.00) + (5.00/5.50) = 1.67 + 0.91 = 2.58
Team Total score : 2.92 + 2.58 = 5.50
Team B bat score: (37/30)*(75.5/75) + (43/30)*(95.56/75) = 1.25 + 1.83 = 3.08
Team B bowl score: (30/15)*(5.00/6.00) + (30/20)*(5.00/4.00) = 1.66 + 1.88 = 3.54
Team B total score: 3.08 + 3.54 = 6.62
Thus Team B would win the head to head matchup by a score of 6.62 to 5.50.